5.4 Practice Problems#
Determine the oxidation number of each atom in the following compounds and ions:
\(\ce{SO2}\)
\(\ce{NaH}\)
\(\ce{CO3^2-}\)
\(\ce{N2O5}\)
Rank the following sets of chemical compounds from the most oxidized to the most reduced form:
\(\ce{NH3}\), \(\ce{NO3-}\), \(\ce{NO2-}\), \(\ce{N2}\)
\(\ce{H2SO4}\), \(\ce{SO4^2-}\), \(\ce{H2S}\), \(\ce{SO2}\), \(\ce{SO3}\)
\(\ce{Cr(s)}\), \(\ce{K2Cr2O7}\), \(\ce{H2CrO4}\), \(\ce{Cr(OH)2-}\)
Balance the reactions below. Identify the oxidizing and reducing agents in the balanced reactions.
Permanganate ion (\(\ce{MnO4^-}\)) and iodide (\(\ce{I-}\)) ion react in basic solution to produce manganese(IV) oxide (\(\ce{MnO2}\)) and molecular iodine (\(\ce{I2}\)) as follows: \( \ce{ MnO4^- + I- -> MnO2 + I2} \)
One of the common ways to treat groundwater contaminated with \(\ce{Cr(VI)}\) is by using \(\ce{Fe}\) minerals, as shown by the following reaction: \(\ce{Fe^2+ + Cr2O7^2- -> Fe^3+ + Cr^3+} \)
\(\ce{SO2(g)}\) in air is mainly responsible for the phenomenon of acid rain. Typically, \(\ce{SO2}\) generated at the source can be treated by scrubbing the acid rain with a standard permanganate solution as follows: \( \ce{SO2 + MnO4- -> SO4^2- + Mn^2+} \)
The concentration of a hydrogen peroxide (\(\ce{H2O2}\)) solution can be conveniently determined by titration against a standardized permanganate (\(\ce{MnO4-}\)) solution in an acidic medium according to the following unbalanced equation: \(\ce{MnO4- + H2O2 -> O2 + Mn^2+} \)
Organic matter in soils and natural water strongly influences redox processes. In the reaction below, organic matter (\(\ce{CH2O}\)) is represented in a simplified form: \( \ce{CH2O + NO3- -> HCO3- + N2 + CO2} \)
Calculate \(pe\) in the following examples:
Calculate \(pe\) for natural water at \(p\ce{H} = 7.5\) in equilibrium with atmosphere. \(P_{\ce{O2}} = \pu{0.21 atm}\) & \(K=\pu{e83}\). The half-reaction: \(\ce{O2 + 4 H+ + 4 e- -> 2 H2O} \)
Calculate \(pe\) for natural water at \(p\ce{H} = 8\) containing \(\ce{Mn^2+} = \pu{e-5 M}\) at equilibrium with \(\ce{\gamma-MnO2}\) & \(K=\pu{e41}\). The half-reaction: \(\ce{\gamma-MnO2 + 4 H+ + 2 e- -> Mn^2+ + 2 H2O} \)
Show the \(pe-p\ce{H}\) relationships for the following systems:
Oxidation of \(\ce{H2O(l)}\) to \(\ce{O2(g)}\).
Reduction of \(\ce{H2O(l)}\) to \(\ce{H2(g)}\).
Sulfur is commonly present in coastal environments, such as those near Charleston, SC. Three of the most common forms of \(\ce{S}\) in these environments are \(\ce{SO4^2-}\), \(\ce{S (s)}\), and \(\ce{H2S}\). Answer the following questions:
Write three balanced half-reactions between each pair of \(\ce{S}\) species, listed above.
Write the \(pe\) expressions for all of the above half-reactions.
If \(\log K =4.8\) and \(36.2\) for fully balanced \(\ce{S(s)}-\ce{H2S}\) and \(\ce{SO4^2-}-\ce{S(s)}\) half-reactions, respectively, determine \(\log K\) for the balanced half-reaction \(\ce{SO4^2-}-\ce{H2S}\).
Of all forms of S present in these coastal environments, which form of \(\ce{S}\) will predominate at \(p\ce{H} = 4\) and \(pe = -3\)? Hint: Substitute these values in the 3 \(pe\) expressions in part (2).
If the concentrations of \(\ce{S}\) species in each redox couple (see parts (1) and (2) of this problem) are equal, write the new \(pe\) expressions.